1.What is the cross section formed by a plane that contains a vertical line of symmetry for a tetrahedron?

Mathematics

2 answers:

stiks02 [169]4 years ago

7 0

1. Answer;

- Triangle

Explanation;

The cross section formed by a plane that contains a vertical line of symmetry for a tetrahedron is a Triangle.

A tetrahedron also a triangular pyramid, is a polyhedron composed of four triangular faces, six straight edges, and four vertex corners.

2. Answers

- Triangle

Explanation;

The cross section formed by a plane that intersects three faces of a cube is a Triangle. A cross section is the shape we get when cutting straight through an object. The shape of the cross-section of a solid depends upon the orientation of the cutting plane to the solid.

soldier1979 [14.2K]4 years ago

7 0

1. The cross section formed by a plane that contains a vertical line of symmetry for a tetrahedron is:
A ) triangle.
2. The cross section formed by a plane that intersects three faces of a cube is:
A ) triangle.

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Civil an airport, a factory, and a shopping center are at the vertices of a right triangle formed by three highways. the airport

vekshin1

Answer:

<em>The shortest possible length for the service road is 2.88 miles.</em>

Step-by-step explanation:

According to the below diagram, $A, B$ and $C$ are the positions of airport, shopping center and factory respectively.

Given that, $AB= 3.6 miles, BC= 4.8 miles$ and $AC= 6.0 miles$

In right triangle $ABC$

$tan(\angle ACB)=\frac{AB}{BC} \\ \\ tan(\angle ACB)= \frac{3.6}{4.8}=0.75\\ \\ \angle ACB= tan^-^1(0.75)=36.8698.... degree$

The shortest possible length for the service road from the shopping center to the highway that connects the airport and factory is $BD$ .

That means, $\triangle BCD$ is also a right triangle in which $\angle BDC=90\°$ , Hypotenuse $(BC)= 4.8$ miles and $BD$ is the opposite side in respect of $\angle DCB$ or $\angle ACB$ .