A can of mixed nuts contains 46 pecans and 52 other nuts. What is the probability that a randomly selected nut will be a pecan?
Simplify your answer and write it as a fraction or whole number.
1 answer:
There are 98 nuts in total (46+52=98) and 46 of them are pecan nuts
46/98 =23/49 chance
You might be interested in
Answer:
V= 105cm^3
Step-by-step explanation:
V=volume
(1/3)V+40=(5/7)V
(5/7)V-(1/3)V=40
(15/21)V-(7/21)V=40
(8/21)V=40
(21/8)(8/21)V=(21/8)(40
V=21*5
V=105 cm3
(1/3)(105)=35, 35+40=75, 75/105=15/21=5/7
Tan(x)= 33/105
x = arctan(33/105)
x = 17.44718842 degrees.
Answer:
13x+13y
Step-by-step explanation:
(combine like terms)
8x+5x=13x
7y+4y+2y=13y
hope this helped you!
