Answer:
156 boxes
Step-by-step explanation:
Simply divide the total amount of eggs (937) by the amounts which are packaged in the boxes (6)
937 / 6 = 156 
So there are 156 full boxes and 1 egg left
Since you can't pack one egg, the answer is 156 boxes
Answer:
All the values greater than the number 4 are possibles values for this number:
Step-by-step explanation:
Let x is the number mentioned:
Six times a number : 6 ( x )
Twenty more than the number: 20 + x
6 x > 20 + x
Solving the inequality
6 x - x > 20
5x > 20
x > 
x > 4
Two whole numbers whose least common denominator is 36 could be many different pairs: 1 and 36, 2 and 36, 3 and 36, 4 and 36, 4 and 18, 4 and 9, 6 and 36, 9 and 36, 9 and 12, 12 and 36, 12 and 18, 18 and 36, and lastly 36 and 36.
If you want fractions in simplest form, with different denominators, and with an LCD of 36, I would go with 4/5 and 9/13.
I think the reason these work is because 5, 13, and 36 are all pairwise relatively prime (meaning the LCD of any two of them is their product), and because the LCD of 4 and 9 is 36, like I said earlier.
Answer:
B
Step-by-step explanation:
Using the cofunction identity
sin x = cos(90 - x)
Given
sin(3x + 19) = cos(5x - 25), then
3x + 19 = 90 - (5x - 25)
3x + 19 = 90 - 5x + 25
3x + 19 = 115 - 5x ( add 5x to both sides )
8x + 19 = 115 ( subtract 19 from both sides )
8x = 96 ( divide both sides by 8 )
x = 12 → B
Answer:
the second answer seems to be the most reassonable
Step-by-step explanation:
