Answer:
is there supposed to be a picture or something so ik what the choices are?
Step-by-step explanation:
Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
about $3 because...
and
which is probably as close as your gonna get
Answer:
Step-by-step explanation:
You have a half sphere and a cylinder.
Trick question! Note that the diameter of the cylinder is in meters, while the height is given in centimeters.
For cylinder:
radius r = 5 m
height h = 6 cm = 0.06 m
volume = πr²h = π(5²)(0.06) = 1.5π m³
For sphere:
radius r = 5 m
volume of sphere = (4/3)πr³
volume of half sphere = (2/3)πr³ = (2/3)π5³ = (250/3)π m³
Total volume = 1.5π + 250π/3 ≅ 266.5 m³
