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AnnyKZ [126]
2 years ago
12

Which statement about the slope of a line is true?

Mathematics
1 answer:
Fudgin [204]2 years ago
8 0

Answer:

B) A line with a positive slope increases as it is viewed from left to right.

Step-by-step explanation:

A line with a positive slope increases as it is viewed from left to right.

A positive slope means that as a line on the line graph moves from left to right, the line rises.

Hope this helps :)

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WILL GIVE A BRAINLIEST!! PLEASE HELP!!
OLga [1]
The domain of the function is the set of all x's that are suitable for the given equation. In the problem, we are asked to determine the equation with the most restricted domain. Option A can have x from negative infinity to positive infinity as well as option B and option D. OPtion C can only have x equal to zero and all positive numbers. Hence the answer is C. hope that helped
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3 years ago
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Which of the following is equal to the rational expression when x doesnt equal 5? x^2 - 25/ x - 5
scoundrel [369]
The complete question in the attached figure

we have that
(x²<span> - 25)/ (x - 5)

we know
</span>(x² - 25)-------------> (Difference of two squares)----------> (x+5)*(x-5)

then

(x² - 25)/ (x - 5)<span>-------> (x+5)*(x-5)/(x-5)------------> (x+5)

the answer is the option B)
(x+5)</span>

4 0
3 years ago
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Lydia found an apartment that she wants to rent. The rent is $715 per month and there is a security deposit of $355. To move in,
bonufazy [111]

Answer:

$1785

Step-by-step explanation:

you have to multiply the monthly rent by 2 since she has to pay the first and last months rent and then add the $355 security deposit

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2 years ago
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Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A balloon, rising vert
Liula [17]

Answer:

(a) 2.79 seconds after its release the bag will strike the ground.

(b) At a velocity of 73.28 ft/second it will hit the ground.

Step-by-step explanation:

We are given that a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 80 feet above the ground.

Assume the acceleration of the object is a(t) = −32 feet per second.

(a) For finding the time it will take the bag to strike the ground after its release, we will use the following formula;

                        s=ut+\frac{1}{2} at^{2}

Here, s = distance of the balloon above the ground = - 80 feet

          u = intital velocity = 16 feet per second

          a = acceleration of the object = -32 feet per second

          t = required time

So,  s=ut+\frac{1}{2} at^{2}

      -80=(16\times t)+(\frac{1}{2} \times -32 \times t^{2})

       -80=16t-16 t^{2}

       16 t^{2} -16t -80 =0

          t^{2} -t -5 =0

Now, we will use the quadratic D formula for finding the value of t, i.e;

           t = \frac{-b\pm \sqrt{D } }{2a}

Here, a = 1, b = -1, and c = -5

Also, D = b^{2} -4ac = (-1)^{2} -(4 \times 1 \times -5) = 21

So,  t = \frac{-(-1)\pm \sqrt{21 } }{2(1)}

      t = \frac{1\pm \sqrt{21 } }{2}

We will neglect the negative value of t as time can't be negative, so;

t = \frac{1+ \sqrt{21 } }{2} = 2.79 ≈ 3 seconds.

Hence, after 3 seconds of its release, the bag will strike the ground.

(b) For finding the velocity at which it hit the ground, we will use the formula;

                       v=u+at

Here, v = final velocity

So,  v=16+(-32 \times 2.79)

      v = 16 - 89.28 = -73.28 feet per second.

Hence, the bag will hit the ground at a velocity of -73.28 ft/second.

8 0
3 years ago
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Leokris [45]

Answer:

i dont remember how to answer this so heres some info from the graph.

the y-intercept of the first equation is 8.

the y-intercept of the second equation is 18.

the equations cross at (10,4)

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