Here’s your answer lemme know if it’s not clear
Answer:
2. 10
3. D. 1 for all n
Step-by-step explanation:
2. The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^b = 1/a^-b
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The value of n is 10.
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3. Using the above rules of exponents, the expression simplifies to ...
6^(-n+n) = 6^0 = 1
The value is 1 for any n.
Answer:
I think it's the first one... but I'm not pretty sure.
The equation for the quadratic variation is:
y = kx^2
Plug in x and y values to solve for 'k'
32 = k(2^2)
32 = 4k
k = 32/4 = 8