Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711
Answer: 896
Step-by-step explanation:
Let's use a rule of three here.
Solve for x;
Answer:
4 units ...................
Answer:
4,9
Step-by-step explanation:
i looked it up on a website,uhhhhh i don't know if its completely write soooo.....
Answer:
<h2>D. √136</h2><h2 />
Step-by-step explanation:
see attached sketch
