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daser333 [38]
4 years ago
5

2. Trey measured the mass of some pebbles What is the combined mass of the pebbles that are 4 1/2 grams or more?

Mathematics
1 answer:
Romashka-Z-Leto [24]4 years ago
3 0

Answer:

40

Step-by-step explanation:

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I need some help if you could
Fed [463]

Step-by-step explanation:

35A) arc AC = 360-(100+110+80)=

360-290 = 70°

35B) <em>L</em><em> </em>D = ½× 70 = 35°

35C) <em>L</em><em> </em>AEC = ½(100+70)=½×170= 85°

35D) <em>L</em><em> </em>P = ½(100-70) = ½×30 = 15°

5 0
3 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

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How to write the number 63 in four different ways
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63^1
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3 years ago
you roll a six sided number cube and flip a coin what is the probability of rolling a number greater than 5 and flipping heads?
Whitepunk [10]

Answer:

0.08333... or 8.333...%

Step-by-step explanation:

1/6 * 1/2 = 1/12

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3 years ago
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Answer:

yes

Step-by-step explanation:

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