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Jobisdone [24]
3 years ago
12

Based on the table, which best predicts the end behavior of the graph f(x)??​

Mathematics
1 answer:
tatuchka [14]3 years ago
5 0

Answer:

It looks to be A

Step-by-step explanation:

Because for f(x) it is randomly going positive and negative while x is slowly going from negative to positive so it changes up between positives and negatives due to the f(x)

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Jacob buys for muffins for $5 what is the cost of 7 muffins​
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Answer:

35$

Step-by-step explanation:

If one muffin is 5 dollars and you buy 7 then just multiple them and get 5x7=35

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A student records a physical property of a rock as 2.2N. Which physical property has the student measured?
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I think weight, Newton’s maybe
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A mallard duck is 56 to 65 cm long if the duck travel 97.8 miles at top speed in 1.5 hours how far did it travel in 1 hour
ra1l [238]

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They traveled 2.71 in 1 hr

Step-by-step explanation:

97.8 divided by 1.5 then multiply that by 1hr

6 0
2 years ago
Can someone help me answer this
lions [1.4K]

Answer:

sum the numbers of favorite food together.

pizza- 58.

hamburger- 36.

pasta- 14.

others- 17.

Addition of the favorite food will give us .

58+36+14+17=125.

pizza ..58/125 × 100 =46.4

3 0
1 year ago
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
3 years ago
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