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4 years ago

Based on the table, which best predicts the end behavior of the graph f(x)??

Mathematics

1 answer:

tatuchka [14]4 years ago

5 0

Answer:

It looks to be A

Step-by-step explanation:

Because for f(x) it is randomly going positive and negative while x is slowly going from negative to positive so it changes up between positives and negatives due to the f(x)

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The ratio 30 in. To 9ft in simplest form

dangina [55]

Convert "inches" to "feet" here. 30 in 1 ft 30
--------- = --------- = --------- ft
1 12 in 12

Now find the ratio of (30 ft / 12) to 9 ft:

30 ft
------
12 30
==== = ----------- Reduce this fraction; one way would be to
9 ft 12(9) write 30/9 as 10/3:

30 10
------- = ------------ = 5/18 (answer)
12(9) 12(3)

8 0

4 years ago

Read 2 more answers

‼️‼️‼️‼️HELP‼️‼️‼️‼️‼️‼️‼️

Vesnalui [34]

Michael took the return trip at a velocity 33.75 miles per hour.

<h3>How fast did Michael drive in his return trip?</h3>

Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.

First trip

45 = s / 3 (1)

Second trip

v = s / 4 (2)

By (1) and (2):

45 · 3 = 4 · v

v = 33.75 mi / h

Michael took the return trip at a velocity 33.75 miles per hour.

To learn more on velocities: brainly.com/question/18084516

#SPJ1

3 0

2 years ago

CAN U PLZ ANSWER IT?

Vadim26 [7]

So you subtitute into the equation
so T=RH
if R=10 and H=35
so 10 per hour so
10 times 35 or (R times H)
so 350=T

b.
if is R=12 and H=40
subsitute and get
12 times 40 (RH) which is
480=T

4 0

3 years ago

Read 2 more answers

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

4 years ago

There is 240 mg of sodium for 36 crackers. How much sodium for 15 crackers.

muminat

100. You would divide the original amount of crackers by 240, then multiply by the new amount of crackers.

4 0

3 years ago

Based on the table, which best predicts the end behavior of the graph f(x)??​

Based on the table, which best predicts the end behavior of the graph f(x)??