Answer:
0.5 < t < 2
Step-by-step explanation:
The function reaches its maximum height at ...
t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)
The function can be factored to find the zeros.
f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)
The factors are zero for ...
x = -1 and x = +2
The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.
Answer:
sqrt. 244
Step-by-step explanation:
a^2 + b^2 =c^2
10^2 + 12^2 =244
c^2 =244
c= sqrt. 244
-2.1 because each dash represents 0.1
Given parameters:
Weight of Tan = 146pounds
Unknown:
Weight of Minh = ?
Following this problem step wisely, we can derive a solvable algebraic equation;
Let the weight of Minh = M
In the second sentence, we see that Minh weighs 15pounds more than Tan;
So;
M = 15 + Weight of Tan
Since we already know the weight of Tan,
Weight of Minh = 15 + 146 = 161pounds
We clearly see that Minh's weight will be 161 pounds.
Answer:
h is the answer
Step-by-step explanation: