Answer:
The angle it turns through if it sweeps an area of 48 cm² is 448.8°
Step-by-step explanation:
If the length of a minute hand of a clock is 3.5cm, to find the angle it turns through if it sweeps an area of 48 cm, we will follow the steps below;
area of a sector = Ф/360 × πr²
where Ф is the angle, r is the radius π is a constant
from the question given, the length of the minute hand is 3.5 cm, this implies that radius r = 3.5
Ф =? area of the sector= 48 cm² π = 
we can now go ahead to substitute the values into the formula and solve Ф
area of a sector = Ф/360 × πr²
48 = Ф/360 × × (3.5)²
48 = Ф/360 × ×12.25
48 = 269.5Ф / 2520
multiply both-side of the equation by 2520
48×2520 = 269.5Ф
120960 = 269.5Ф
divide both-side of the equation by 269.5
448.8≈Ф
Ф = 448.8°
The angle it turns through if it sweeps an area of 48 cm² is 448.8°
13.5 = 30% of 45
4.5 = 15% of 30
4.6 = 23% of 20
4.2 = 60% of 7
Hope this helps!!
Answer:
1/36
Step-by-step explanation:
Attached is a chart showing the 36 possible outcomes for rolling 2 number cubes. The sum of the two cubes is 12 in only one of the outcomes (both sixes). The probability is 1/36.
<span>Find force,
9.8 m/s2 x 5.24 kg = </span><span>51.352 N </span>
Find work,
<span><span>51.352 N x 1.63 m= </span><span>83.70 N*m
</span>Example:
To solve this given word problem we can first identify the given and the apt formula to use in this phenomenon: Given: Force = 4, 500 N = 4, 500 kg-m/s^2 Acceleration = 5 m/s^2 </span>
<span>Formula: f=ma </span>
<span>Derivation: m = f/a </span>
<span>Solution: </span><span><span>
1. </span>M = f/a</span> <span><span>
2. </span>M = 4,500 kg-m/s^2 / 5 m/s^2</span> <span><span>
3. </span>M = 900 kg </span>
<span>Hence, the object’s mass is </span>900 kg.<span>
</span>
Answer:
Step-by-step explanation:
Let the smaller number be 
. Since they are consecutive even numbers, the larger number can be represented by 
.
Therefore, we have the following equation:
Thus, the larger number is 
