All categories

3 years ago

Given JL=4x,JL=4x, JK=2x+3,JK=2x+3, and KL=x,KL=x, determine the numerical length of \overline{KL}.

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

4 0

Answer:

KL = 3

Step-by-step explanation:

It appears we are to assume that K lies between J and L, so we have ...

JK +KL = JL

(2x+3) +(x) = (4x)

3x +3 = 4x

3 = x . . . . . . . subtract 3x

KL = 3

You might be interested in

5|2x + 4| – 3 = -3<br> Please help!

stellarik [79]

The answer is X=-2
Hope it helps!

3 0

2 years ago

Let x ∼ bin(9, 0.4). find

Kobotan [32]

A.
$\mathbb P(X>6)=\mathbb P(X=7)+\mathbb P(X=8)+\mathbb P(X=9)$
$=\dbinom97(0.4)^7(1-0.4)^{9-7}+\dbinom98(0.4)^8(1-0.4)^{9-8}+\dbinom99(0.4)^9(1-0.4)^{9-9}$
$\approx0.025$

b.
$\mathbb P(X\ge2)=1-\mathbb P(X$
$=1-\dbinom90(0.4)^0(1-0.4)^{9-0}-\dbinom91(0.4)^1(1-0.4)^{9-1}$
$\approx0.929$

c.
$\mathbb P(2\le X$
$=\dbinom92(0.4)^2(1-0.4)^{9-2}+\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}$
$\approx0.663$

d.
$\mathbb P(2$
$=\dbinom93(0.4)^3(1-0.4)^{9-3}+\dbinom94(0.4)^4(1-0.4)^{9-4}+\dbinom95(0.4)^5(1-0.4)^{9-5}$
$\approx0.669$

e.
$\mathbb P(X=0)=\dbinom90(0.4)^0(1-0.4)^{9-0}\approx0.01$

f.
$\mathbb P(X=7)=\dbinom97(0.4)^7(1-0.4)^{9-7}\approx0.021$

g, h.
For $X\sim\mathcal B(n,p)$ , recall that $\mathbb 
E[X]=\mu_X=np$ and $\mathbb V[X]={\sigma_X}^2=np(1-p)$ . So

$\mu_X=9(0.4)=3.6$
${\sigma_X}^2=9(0.4)(0.6)=2.16$

6 0

3 years ago

Please help I’ll mark you as brainliest if correct

nadezda [96]

Answer:

I think it is c

Step-by-step explanation:

because if you try to solve it you get that answer

5 0

2 years ago

What is the equation for this graph?

DanielleElmas [232]

Answer: Im sorry but there is no graph m8

3 0

3 years ago

1. A quadratic equation can have all of the following number of solutions except

mina [271]

You cannot have infinite solutions.

7 0

2 years ago