Sin(θ - 180)
sin(θ)cos(180) - cos(θ)sin(180)
sin(θ)[-1] - cos(θ)[0]
-sin(θ) - 0
-sin(θ)
X - 2y= 14
x - 3y= - 11 | * ( -1)
x - 2y = 14
-x + 3y= 11
----------------
/ y= 25
x - 2*25= 14
x - 50 =14
x= 14+50
x=64
Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:

Introducing the constant of proportionality

If 150 pounds is required for a distance of 10 inches from the object

Therefore, the relationship between p and d is:

When d=3 Inches

The pressure applied when the distance is 3 inches is 500 pounds.
Answer:
C
Step-by-step explanation:
Area = π
r means radius
radius = d/2
d = diameter
8 /2 = 4
4 is radius
= 16
^ ( its 4 x 4 ) ^
so then,
Area = 16π