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aliya0001 [1]
3 years ago
9

What is the domain of the function shown in the table.

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

Option B.

Step-by-step explanation:

A function is represented by the table given in the question.

We should always remember that for a function plotted on a graph or table representing x and y-coordinates, x value will always represent Domain and y- values define the range of the function.

Therefore x values {2, 4, 6, 8} represent the domain of the function and y values represent the range.

Option B. {2, 4, 6, 8} is the answer.

Darina [25.2K]3 years ago
5 0

the domain is your x values so it is B

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Answer: (x+10)^2+(y+6)^2=121

Step-by-step explanation:

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The equaton of  a circle in standard form is:

(x-h)^2+(y-k)^2=r^2

Where the center is at <em>(h, k)</em> and <em>r</em> is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

x^{2}+y^2+20x+12y+15=0

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

(x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121

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