(tan(<em>x</em>) + cot(<em>x</em>)) / (tan(<em>x</em>) - cot(<em>x</em>)) = (tan²(<em>x</em>) + 1) / (tan²(<em>x</em>) - 1)
… = (sin²(<em>x</em>) + cos²(<em>x</em>)) / (sin²(<em>x</em>) - cos²(<em>x</em>))
… = -1/cos(2<em>x</em>)
Then as <em>x</em> approaches <em>π</em>/2, the limit is -1/cos(2•<em>π</em>/2) = -sec(<em>π</em>) = 1.
Answer:
$178.3
Step-by-step explanation:
The value of a car is $20,000
The car loses 10.7% of its value yearly
Since there are 12 months in a year then 10.7% can be represented as
10.7%/12
= 0.8916%
Therefore the approximate monthly decrease in value can be calculated as follows
= $20,000×0.8916/100
= $20,000×0.008916
= $178.3
Hence the approximate monthly decrease in value is $178.3
Answer:
375 in² is the answer.
Step-by-step explanation:
Are of rectangle= area of 2 triangle
= 1/2*25*15+1/2*25*15
=187.5+187.5
=375 in²
1)
I:y=3x-4
II:9x-3y=14
substitute y into II:
9x-3*(3x-4)=14
9x-9x+12=14
12=14
this is obviously not equal so there is no solution, the lines are parallel
2)
I:y=4x+6
II:5x-y=6
substitute y into II:
5x-(4x+6)=6
5x-4x-6=6
x=12
substiute x into II:
5*12-y=6
-y=6-60
-y=-54
y=54
the solution is (12,54)
18/15/12/9 = 0.0111111111111
Have a great evening. I hope this helped! :)
