<span>The
third root of the given complex number 27(cos(pi/5)+isin(pi/5)) is <span>3(cos(pi/15)+i sin(pi/15))
</span>The solution would be like this
for this specific problem:</span>
<span>2^5 =
32 so you need a 2 out front the 5th root of cos(x) + i sin(x) is
cos(x/5) + i sin(x/5). Additionally, 5 roots are located at even
intervals around the circle. They are spaced every 2 pi/5 or 6 pi/15 radians.
</span>
<span>Roots
are located at pi/15, pi/15+ 10pi/15 = 11 pi/15 and pi/15+ 20pi/15 = 21 pi/15
(or 7 pi /5 ).</span>
The equation for direct variation is y=kx where k is the constant of variation.
Answer:
Step-by-step explanation:
y(y+2)=y²-6
y²+2y=y²-6
2y=-6
y=-3
2[x-(1-3x)]=3(x+1)
2[x-1+3x]=3x+3
2(4x-1)=3x+3
8x-2=3x+3
8x-3x=3+2
5x=5
x=1
3 over 2 is another ratio for X's to O's.
