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3 years ago

9 x minus 10 = 3 x + 2

Mathematics

2 answers:

prohojiy [21]3 years ago

6 0

Answer:

x=2

Step-by-step explanation:

9 x - 10 = 3 x + 2

Subtract 3x from each side

9 x -3x- 10 = 3 x-3x + 2

6x -10 =2

Add 10 to each side

6x-10+10=2+10

6x = 12

Divide each side by 6

6x/6 = 12/6

x = 2

Maslowich3 years ago

6 0

Answer:

x = 2

Step-by-step explanation:

9x - 10 = 3x + 2

9x - 3x = 2 + 10

6x = 12

x = 12/6

x = 2

hope it helps!

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Find the distance between the two endpoints. (-6, 1) and (-3, 1)

AleksAgata [21]

Answer:

Step-by-step explanation:

distance formula

3 0

3 years ago

Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write

Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

Use double point formula and simplify it to get two eqaution.
Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)$

~ Keep all values.

$(y + 4) = \frac{11 + 4}{2 + 1} (x + 1)$

~ Simplify it.

$y + 4 = \frac{15}{3} (x + 1)$

$y + 4 = 5x + 5$

$5x - y + 1 = 0$

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1)$

~ Keep all values.

$(y - 1) = \frac{10 - 1}{4 - 1} (x - 1)$

~ Simplify it.

$y - 1 = 3 x - 3$

$3x - y - 2 = 0$

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

$m1 = \frac{ - coeff. \: of \: x}{coeff \: of \: y}$

$m1 = \frac{ - 5}{ - 1}$

Therefore, m1 = 5

Slope of second equation.

$m2 = \frac{ - coeff \: .of \: x}{coeff \: .of \: y}$

$m2 = \frac{ - 3}{ - 1}$

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

Hope it helps...

6 0

3 years ago

Determine how many zeros, how many real or complex, and find the roots for f(x) = x3 − 5x2 − 25x + 125.

miskamm [114]

We can write this as:-

P(x) = + x^3 - 5x^2 - 25x + 125
There are 2 changes of real sign so by Descartes Rule of signs there are either 2 positive real roots or 0 positive roots.

P(-x) = - x^3 - 5x^2 + 25x + 125
There is just one change of sign so there is exactly 1 real negative root.

125 is a multiple of 5 so By rational root theorem 5 could be a positive root.

P(5) = 125 - 125 - 125 + 125 = 0 so one zero is 5
if we divide the polynomial by (x - 5) we get the quadratic
x^2 - 25
(x + 5)(x - 5) = 0

x = 5,-5

so the roots are 5 (multiplicity 2) and -5.
2 real positive zeroes and one real negative zero

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3 years ago

Solve each system using substitution. Check your answer 2x+2y=38 y=x+3

Mrac [35]

Your answer would be X=8 and Y=11.

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3 years ago

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11Alexandr11 [23.1K]

Answer:

1. The probability that the T-shirt will be grey :-

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