Answer:
0 F
Step-by-step explanation:
-4+4(incressed)=0
12subtract4
12-4
they want me to write more then 20 charaters
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=![\sqrt{(x2-x1)^2+(y2-y1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D)
⇒ ![D = \sqrt{20^2t^2+15(t-1)^2}](https://tex.z-dn.net/?f=D%20%3D%20%5Csqrt%7B20%5E2t%5E2%2B15%28t-1%29%5E2%7D)
Now let ![F(t) = D^2(t)](https://tex.z-dn.net/?f=F%28t%29%20%3D%20D%5E2%28t%29)
∵ ![F'(t) = 800t + 450(t-1) = 1250t -450\\F'(t) =0](https://tex.z-dn.net/?f=F%27%28t%29%20%3D%20800t%20%2B%20450%28t-1%29%20%3D%20%201250t%20-450%5C%5CF%27%28t%29%20%3D0)
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
Answer:it has four side
Step-by-step explanation:
idito
1/2 (8+4)= 6
1/2(-1+4)= 1.5
1/2 (2+4)= 3
1/2 (4+4)= 4
So the correct answer would be A(8)