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Serhud [2]
2 years ago
6

You and your friend share a paper route. You can deliver 4 papers in one minute and your friend can deliver 3 papers in one minu

te. Seventy-five papers have to be delivered each day on the route. Let n be the number of papers you deliver. A) use the verbal model to write an equation that you can use to find out how long it will take the two of you working together to deliver the papers.
Mathematics
1 answer:
nadezda [96]2 years ago
5 0

Answer:

n\times \frac{1}{4}+(75-n)\times \frac{1}{3}

Step-by-step explanation:

Given that:

4 papers are delivered by first person in one minute.

Rate of delivering one paper

or

Time taken to deliver one paper can be calculated by the formula:

\dfrac{\text{Total Time taken}}{\text{Number of papers delivered}}

Time taken to deliver one paper by first person = \frac{1}{4}

3 papers are delivered by second person in one minute.

Time taken to deliver one paper by second person = \frac{1}{3}

Total number of papers = 75

Number of papers delivered by first person = n

So, number of papers delivered by second person = (75-n)

Time taken to deliver n newspapers = Number of newspapers delivered <em>multiplied by </em>Time taken to deliver one newspaper

Time taken by first person = n\times \frac{1}{4}

Time taken by second person = (75-n)\times \frac{1}{3}

So, Total time taken can be written as:

n\times \frac{1}{4}+(75-n)\times \frac{1}{3}

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Step-by-step explanation:


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3 years ago
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
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