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3 years ago

X divided by 6 is 4. What is Z?

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

Answer:

this is so hard

Step-by-step explanation:

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Tyra's family is spending the afternoon in Millersville. They plan to see a movie and then explore

Xelga [282]

Answer: 36+4h=60

36+4h-36=60-36

4h=24

4h÷4=24÷4

h=6

So, after the move they can spend 6 hours there. (6×4=24, 24+36=60, they will spend $60 if they spend 6 hours there, $56 if they spend 5 hours there and don't want to spend $60).

Step-by-step explanation:

3 0

2 years ago

What is X?<br><br> 2.3x-8.7=0.8x-4.2<br><br> pLS hELP

daser333 [38]

Answer:

x = 45/17

Step-by-step explanation:

We can move all x to 1 side and all the numbers to another. You can add 8.7 on both sides and get that 2.3x = 0.8x + 4.5. Next, we subtract by 0.8x on both sides to get that 1.7x = 4.5, where we can then divide by 17/10 on both sides to get that x is equal to 45/10 * 10/17, so that means that x = 45/17.

5 0

2 years ago

The Orlando Solar Bears had a successful season on the ice winning 80% of their games. They won a record of 32 games. How many g

Makovka662 [10]

Answer:

Step-by-step explanation:

You'd do 80% times 32. You have to move the 80 to the left 2 times. then multiply.

7 0

3 years ago

Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t

Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let $\sigma_{1}^{2}$ be the variance for the population of weight gains for rats given a low dose, and $\sigma_{2}^{2}$ the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test $H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2}$ vs $H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}$ . We have that the sample standard deviation for $n_{2} = 22$ female control rats was $s_{2} = 28$ g and for $n_{1} = 18$ female low-dose rats was $s_{1} = 51$ g. So, we have observed the value

$F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176$ which comes from a F distribution with $n_{1} - 1 = 18 - 1 = 17$ degrees of freedom (numerator) and $n_{2} - 1 = 22 - 1 = 21$ degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0

3 years ago

The subject of the formula is y.<br> y = 4x + 3<br> Rearrange the formula to make x the subject

zysi [14]

Answer:

Step-by-step explanation:

y = 4x + 3

To make x the subject send 3 to the other side of the equation

That's

4x = y - 3

<u>Divide both sides by 4 to make x stand alone</u>

$\frac{4x}{4} = \frac{y - 3}{4}$

We have the final answer as

$x = \frac{y - 3}{4}$

Hope this helps you

7 0

3 years ago