Question

Two boxes are placed in front of you. Box A contains 4 white and 2 black

Answer 1

Answer:

The probability that the marble you select is black is 0.5167

Step-by-step explanation:

Let,

$E_1$ the probability of selecting one marble from box A

$E_2$ the probability of selecting one marble from box B

$BB_1$ be the probability of selecting black marble from box A

$BB_2$ be the probability of selecting black marble from box B

Now

$P(E_1) = \frac{1}{2}$

$P(E_2) = \frac{1}{2}$

$P(BB_1) = \frac{2}{6}$

$P(BB_2) = \frac{7}{10}$

P(Selecting a Black Marble )  = $(P(E_1) \times P(BB_1))+(P(E_2) \times P(BB_2))$

=>$(\frac{1}{2} \times \frac{2}{6})+(\frac{1}{2} \times \frac{7}{10})$

=>$(\frac{2}{12})+(\frac{7}{20})$

=>$(\frac{1}{6})+(\frac{7}{20})$

=>$\frac{20 + 42}{120}$

=>$\frac{62}{120}$

=>$\frac{31}{60}$

=>0.5167