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White raven [17]
2 years ago
13

a packe of cards conatins 4 red and 5 black cards. a hand of 5 cards is drawn without replacment. What is the proablity of all f

ive black. of exactly three black?
Mathematics
1 answer:
Vladimir79 [104]2 years ago
5 0

Answer: Our required probability is 0.3387.

Step-by-step explanation:

Since we have given that

Number of red cards = 4

Number of black cards = 5

Number of cards drawn = 5

We need to find the probability of getting exactly three black cards.

Probability of getting a black card = \dfrac{5}{9}

Probability of getting a red card = \dfrac{4}{9}

So, using "Binomial distribution", let X be the number of black cards:

P(X=3)=^5C_3(\dfrac{5}{9})^3(\dfrac{4}{9})^2\\\\P(X=3)=0.3387

Hence, our required probability is 0.3387.

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Which function is quadratic?
PilotLPTM [1.2K]

Answer:

step 1. A, B,D are incorrectly written as these are not all coordinates. they must be written (x, y)

step 2. so the question becomes is C a quadratic

step 3. The x values must be evenly spaced. the x values are evenly spaced by a difference of 4

step 4. write out the y values: -126, -14, 2, 18

step 5. write out the differences: 140, 16, 16

step 6. write out the differences: -124, 0.

step 7. after doing this twice the numbers nust be the same for this to be a quadratic which they aren't

step 8. C is not a quadratic.

8 0
3 years ago
Find the roots of:
Elena-2011 [213]

\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \  2x^3-7x^2+8x-3=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

  | 2  -7    8  -3

<u>1 |      2   -5   3</u>

  | 2   -5    3  0

<u> 1 |      2     -3   </u>

    2   -3     0

So the factorization is (x-1)² (2x-3)=0. So:

                     \bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2}  }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \  x^3-x^2-4=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

      |  1  -1  0  -4

  <u>2  |     2  2     </u>

         1  2  2  0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

                   \bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }

\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \  6x^3+7x^2-9x+2=0 } \end{gathered}$}

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

   | 6    7       9      2

<u>-2 |      -12    10     -2</u>

     6    -5     1       0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

         \bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}

                     \large\displaystyle\text{$\begin{gathered}\sf  \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}

6 0
2 years ago
7:
Alja [10]

359ft

Step-by-step explanation:

5 0
3 years ago
NEED MATH HELP QUICK!!! PlZ HELP!!!
ad-work [718]
Cy + b ÷a
Hope this helps :)
8 0
3 years ago
N
Nataly_w [17]

Answer: four units left and 1 unit up

Step-by-step explanation:

because negative is at the bottom

4 0
3 years ago
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