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3 years ago

. Melissa wants to check the accuracy of the finance charge on her promissory

Mathematics

1 answer:

masha68 [24]3 years ago

5 0

Answer:

Step-by-step explanation:

Idek.

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How many times greater is the population of Illinois than the population of Alaska?

Jet001 [13]

Answer:

17 times

Step-by-step explanation:

IIIinois : 12670000

Alaska : 731545

12670000/731545=17.31

5 0

3 years ago

Read 2 more answers

Determine two compatible numbers to use to estimate the quotient 5,071/62?

Charra [1.4K]

C. Both of those numbers are very close to the original numbers.

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3 years ago

Suppose Adam wants to have $750,000 in his IRA at the end of 30 years. He decides to invest in an annuity paying 6% interest, co

OLga [1]

Answer:

$9486.68

Step-by-step explanation:

The future value of a annuity formula can be used:

FV = P((1+r)^n -1)/r

750000 = P(1.06^30 -1)/0.06

P = 750000(.06)/(1.06^30 -1) = 9486.68

Adam has to contribute $9,486.68 each year to reach his goal.

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3 years ago

Ramkin is going to flip a fair coin 100 times.

Gelneren [198K]

Answer:

50 times

Step-by-step explanation:

You are going to flip a coin 100 times. There are 2 sides. So, what you would do is divide 100 by two because there are two sides. There is a 50% chance that the coin will land on heads, and a 50% chance it will land on tails.

Please let me know if you have any more questions. Hope this helps!

3 0

2 years ago

Write the partial fraction decomposition fro the ration expression below

zlopas [31]

$\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}$
$5x-2=a(x-1)+b$

Since $5x-2=5x-5+3=5(x-1)+3$ , it follows that $a=5$ and $b=3$ , so

$\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}$

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}$
$x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2$
$x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b$

When $x=0$ , you find that $b=2$ . It's also clear that $a=1$ . So the remaining constants must be $1+c=1\implies c=0$ and $2+d=1\implies d=-1$ , and so you get

$\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}$

6 0

3 years ago