Answer:
The number of liters of 50% antifreeze solution is 50 and the number of liters of 90% antifreeze solution is 150
Step-by-step explanation:
Let
x ----> number of liters of 50% antifreeze solution
y ----> number of liters of 90% antifreeze solution
we know that
50%=50/100=0.50
90%=90/100=0.90
80%=80/100=0.80
x+y=200
x=200-y ------> equation A
0.50x+0.90y=0.8(200) -----> equation B
substitute equation A in equation B and solve for y
0.50(200-y)+0.90y=160
100-0.50y+0.90y=160
0.40y=160-100
0.40y=60
y=150 liters
Find the value of x
x=200-y
x=200-150=50 liters
therefore
The number of liters of 50% antifreeze solution is 50
The number of liters of 90% antifreeze solution is 150
I believe it’s b but maybe e or l for the answers to the questions
If you type in both the coordinates it’ll give you the answer on google. That’s how I did this.
Answer:
the answer is A {126,168,189}
Answer:
-7, then -13, then -19
Step-by-step explanation:
Plug in x values to get y.
y = -2(0) - 7
y = 0 - 7
y = -7
y = -2(3) - 7
y = -6 - 7
y = -13
y = -2(6) - 7
y = -12 - 7
y = -19
Hope this helps. :0)
