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iren2701 [21]
3 years ago
7

What transformations change the graph of f(x) to the graph of g(x)? f(x) = 3x2 g(x) = 9x2 - 4

Mathematics
2 answers:
myrzilka [38]3 years ago
3 0

For any function f(x) =y = f(x) + C    ,c<0 the graph shifts down by c units.

For the function y = Cf(x) If C > 1 stretches it in the y-direction .We can stretch or compress it in the x-direction by multiplying x by a constant.

The given function f(x)=3x^{2}.is stretched in y direction by 3 units and shifted down by 4 units to have the graph  g(x)=9x^{2}. -4.




AURORKA [14]3 years ago
3 0
Multiply the whole equation by 3 then subtract 4 from te whole equation
vertically stretched by a factor of 3 and moved down 4 units is the translation
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How do you find the base area of a rectangular prism and a cylinder? Please help
Pani-rosa [81]

Answer:

See explanation.

Step-by-step explanation:

The 'base' of a rectangular prism refers to only one side of the rectangular prism, which is a rectangle.

The formula for the area of a rectangle is as follows:

A=lw

Where A = area, l = length, and w = width.

The 'base' of a cylinder refers to only one side of the cylinder, which is a circle.

The formula for the area of a circle is as follows:

A=\pi r^2

Where A = area and r = radius.

Just in case you typed your question incorrectly and were asking for surface area, here is the formula for surface area for both as well:

Rectangular prism: A=2(wl+hl+hw)\\

Cylinder: A=2\pi rh+2\pi r^{2}

3 0
3 years ago
What is an equation of the line that passes through the point
grin007 [14]

Answer:

y = 5x + 8

Step-by-step explanation:

If you want to find a equation parallel to the line given, you need to know the slope of the line given. Remember that parallel lines have the same slope.

5x - y = 4 and solving for y:

-y = -5x + 4 and solving for positive y:

y = 5x - 4

So the slope of that line is 5. We will use that along with the coordinate given to us to write the equation first in point-slope form then in slope-intercept:

y - (-2) = 5(x - (-2)) and

y + 2 = 5(x + 2) and

y + 2 = 5x + 10 so

y = 5x + 8

8 0
3 years ago
Please help look at the attachment
guajiro [1.7K]

Answer:

i think the answer is that y is 7 and x is 9

Step-by-step explanation: sorry  if this is wrong it probley is

6 0
3 years ago
What is the volume of this solid?
olganol [36]

Answer:452.4

Step-by-step explanation:

6 0
2 years ago
Unsure how to do this calculus, the book isn't explaining it well. Thanks
krok68 [10]

One way to capture the domain of integration is with the set

D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}

Then we can write the double integral as the iterated integral

\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx

Compute the integral with respect to y.

\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)

Compute the remaining integral.

\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}

We could also swap the order of integration variables by writing

D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}

and

\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy

and this would have led to the same result.

\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)

\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)

7 0
1 year ago
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