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3 years ago

Trig question please save mee simplify each expression to one trig function or number

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

5 0

Answer:

sec x

Step-by-step explanation:

tan x * sin x + cos x = (sin x/cos x)sin x + cos x = sin^2 cos x + cos x = (1-cos^2x)/cos x + cos x = 1/cos x - cos x+ cos x = 1/cos x = sec x

NNADVOKAT [17]3 years ago

3 0

Answer:

sec(x)

Step-by-step explanation:

tan x * sinx + cos x

Tan x = sin x/ cos x

Replace tan x in the equation

sinx /cosx * sin x + cos x

sin^2 x / cos x + cos x

We know sin^2 x = 1 -cos^2 x

Replace sin^2 with 1 -cos ^2 x

(1 -cos^2 x) / cos x + cos

Distribute the denominator

1 /cos x - cos x + cos x

Combine like terms

1/cos x

sec x

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HURRY PLEASE

klasskru [66]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=0,\:x=6$

Step-by-step explanation:

Considering the system of the equations

$\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12$

$2x-7y+7y=12+7y$

$2x=12+7y$

Divide both sides by 2

$\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}$

$x=\frac{12+7y}{2}$

$\mathrm{Subsititute\:}x=\frac{12+7y}{2}$

$\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}$

$-\frac{12+7y}{2}+15y=-6$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2$

$-\left(12+7y\right)+30y=-12$

$-12+23y=-12$

$-12+23y+12=-12+12$

$23y=0$

$\mathrm{Divide\:both\:sides\:by\:}23$

$\frac{23y}{23}=\frac{0}{23}$

$y=0$

$\mathrm{For\:}x=\frac{12+7y}{2}$

$\mathrm{Subsititute\:}y=0$

$x=\frac{12+7\cdot \:0}{2}$

$x=\frac{12}{2}$

$x=6$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=0,\:x=6$

4 0

4 years ago

As the sample size becomes larger, the sampling distribution of the sample mean approaches a _____. a. binomial distribution b.

kkurt [141]

Answer:

c. normal probability distribution

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

By the Central Limit Theorem, it is a normal distribution, so option c.

7 0

3 years ago

What is another name for a cord that passes through the center of a circle

FrozenT [24]

Answer:

Equal chords are subtended by equal angles from the center of the circle. A chord that passes through the center of a circle is called a diameter, and is the longest chord.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If half of a pie is eaten what part remains

Alexandra [31]

It depends on the fraction. If it is 10nth of a pie then it would be 5/10 if it is two then 1/2

4 0

3 years ago

Read 2 more answers

One mixture contains 6 fluid Ounces of water and 10 fluid Ounces of vinegar. A second mixture

Nadya [2.5K]

Answer:

The mixtures are not proportional.

3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.

its =3

Step-by-step explanation:

The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.

Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5

Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.

Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4

Therefore, the mixtures are not proportional.

Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.

So,

⇒ 12 + x = 15

⇒ x = 3 fluid ounces.

Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer

5 0

2 years ago