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Alekssandra [29.7K]
3 years ago
14

What is the greatest common factor of 48 and 68

Mathematics
2 answers:
lesya692 [45]3 years ago
4 0

Answer: The Greatest common factor is 48 and 68 is simply 4.

Step-by-step explanation:

factors:

48: 1, 2, 3, 4, 6, 8, 12, 16, 24, & 48

68: 1,2, 4, 17 34, & 68

Zolol [24]3 years ago
3 0

Answer:4

Step-by-step explanation:

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Since x=3 that means all of the x's would be 3's
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Whenever you sign a lease for an apartment, you typically have to pay a security deposit before you even move in; this is in cas
likoan [24]
The answer is F(x) = 900x + 600

Let x stands for the number of months

The apartment is rented for $900 a month, so every month it will be paid 900x (for example, for one month (x = 1), you will pay 900 · 1 = $900, for three months (x = 5), you will pay 900 · 5 = $4500, etc.)

A security deposit is paid only once and is not dependent on the number of months. So, its value is only 600. 

These two values must be summed up because both must be paid, nothing is to subtract. Therefore, the function f(x) for  apartments that rent for $900 a month and a security deposit of $600 is:
f(x) = 900x + 600
7 0
3 years ago
Find S15 for the geometric series 72 + 12 + 2 + +…
Sedbober [7]
S_{15}=72+12+\cdots+\dfrac1{181398528}+\dfrac1{1088391168}
S_{15}=72\left(\dfrac16\right)^0+72\left(\dfrac16\right)^1+\cdots+72\left(\dfrac16\right)^{13}+72\left(\dfrac16\right)^{14}
S_{15}=72\displaystyle\sum_{i=1}^{15}\left(\frac16\right)^{i-1}

\dfrac16S_{15}=72\displaystyle\sum_{i=1}^{15}\left(\frac16\right)^i

\implies S_{15}-\dfrac16S_{15}=72\displaystyle\sum_{i=1}^{15}\bigg(\left(\dfrac16\right)^{i-1}-\left(\dfrac16\right)^i\bigg)
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\dfrac56S_{15}=72\left(1-\dfrac1{6^{15}}\right)
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6 0
3 years ago
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Naddika [18.5K]
The answer is 72,070


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4 0
4 years ago
Please help find the inequalities
saul85 [17]

Answer:

I and III

Step-by-step explanation:

5x - 10 \leq - 5 <=>

5x \leq 5 <=>

x \leq 1

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For II:   9 \leq 1   False

For III:   1 \leq 1   Correct

Hence, I and III is the final answer.

7 0
3 years ago
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