Question

Help me plss, number 2.​

Answer 1

Answer:

At (-2,0) gradient is -4 ; At (2,0) gradient is 4

Step-by-step explanation:

For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).

y = x^2 - 4

y' = 2x

The function y = x^2 - 4 cross the x-axis when:

y = x^2 - 4

0 = x^2 - 4

4 = x^2

2 +/- = x

Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).

The gradient at these points are as follows:

y' = 2(-2) = -4

y' = 2(2) = 4

Cheers.