Option 1To find the y-intercept of a quadratic that is in factor formed follow the steps below:
First take the factor form and put it into standard quadratic form
Standard quadratic form:
To put the the factor form of a qudratic into standard form, we use the foil method
(x-6)(x-2) =

Now to find the y-intercept, input 0 where the x is located:



y-intercept = (0,12)
Why did I use 0? Remember the y-intercept is where the line crosses the y axis so this means the x value of the y intercept is always = 0. Also, not, to find the y-intercept, you could of just multiplied the 6 and 2 in the factored form to get the 12 and since you know that the x is always 0 at the y-intercept, you know that the y-intercept is at (0,12)
Option 2Input 0 for x in f(x) = (x-6)(x-2)
f(x) = (x-6)(x-2)
f(0) = (0 - 6)(0 - 2)
f(0) = (6)(2) = 12
x = 0
f(0) = y = 12
y-intercept = (0,12)
Well the square root of 5 is 2.3607 and if you add four to that you get 6.3607. is this what you are asking?
Step-by-step explanation:
conditional :
3-2x ≥ 0
-2x ≥-3
x ≤ 3/2
1-x ≥ 0
-x≥ -1
x ≤ 1
so, the domain is:
{ x | x € the Real numbers, x ≤ 1}
Answer:
a =
and b =
Step-by-step explanation:
As we know, the radius of the unit circle is 1 unit (it is the hypotenuse in the right triangle, the blue line)
We use trigonometric formulas to find out a and b
- Sin(45) = opposite side / hypotenuse
<=> Sin(45) = b / 1
<=> b= Sin(45)*1 =
- Cos(45) = adjacent side / hypotenuse
<=> Cos(45) = a / 1
<=> a = Cos(45)*1 = 
So: a =
and b =
<span>Tan(x)=2
Or for x=45 tan(x)=1
then for tan(x)=2 ; x must be superior to 45
Then the answer is </span><span>d. 63.4 degrees</span>