Answer:
Step-by-step explanation:
<u>Statements </u> <u> Reasons</u>
1) QS =42 Given
2) QR + RS = QS Segment Addition Postulate
3) (x + 3) + 2x = 42 Substitution Property
4) 3x + 3 = 42 Simplify
5) 3x = 39 Subtraction Property of Equality
6) x=13 Division Property of Equality
Explanation:
We have given QS=42. We have to prove that x=13
We will use Segment Addition Postulate which states that given 2 points Q and S, a third point R lies on the line segment QS if and only if the distances between the points satisfy the equation QR + RS = QS.
Then we will substitute the values in the defined postulate.
where QR= x+3
RS=2x
QS=42
QR+RS=QS
(x+3)+2x= 42
Now simplify the expression by opening the brackets.
x+3+2x=42
3x+3=42
Now subtract 3 from both sides.
3x+3-3=42-3
3x=39
divide both sides by 3.
3x/3 =39/3
x=13..
Answer:
40π/3 cm^2
Step-by-step explanation:
The centerline of the shaded region has a radius of 3 +4/2 = 5 cm. Its length is 1/3 of a circle with that radius, so is ...
length of centerline = (1/3)(2π·5 cm) = (10/3)π cm
The shaded region is 4 cm wide, so the area is the product of that width and the centerline length:
(4 cm)(10/3 π cm) = 40π/3 cm^2
Answer:
dV = - 5.73*10⁹ m³/s
Step-by-step explanation:
Question: What is the rate of change of the volume of the prism at that instant (in cubic meters per second) ?
A function can be dependent on one or more variables. The change in the function due to a change in one o its variables is given by the functions derivative with respect to that variable. For functions that are composed of products of its variables, we may use the product rule to determine its derivative.
The volume of a square prism with base a and height h is given by
V = a²h
When the base and height are changing, we have
dV = 2ah(da/dt) + a²(dh/dt)
Given
a = 4 Km
h = 9 Km
da/dt = - 7 Km/min
dh/dt = 10 Km/min
we have
dV = 2(4 Km)(9 Km)(- 7 Km/min) + (4 Km)²(10 Km/min)
⇒ dV = - 504 Km³/min + 160 Km³/min = - 344 Km³/min
⇒ dV = - 5.73*10⁹ m³/s
4(9+7) = 36+28 = 64
open the parentheses, then simplify.
