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Naya [18.7K]
2 years ago
9

Enter the value of h(-4) for h(x)=(x-2)2+3x in the box.

Mathematics
2 answers:
-Dominant- [34]2 years ago
7 0

Step-by-step explanation:

please mark me as brainlest

mojhsa [17]2 years ago
4 0

\\ \rm\longmapsto h(x)=(x-2)^2+3x

\\ \rm\longmapsto h(-4)=(-4-2)^2+3(-4)

\\ \rm\longmapsto h(-4)=(-6)^2-12

\\ \rm\longmapsto h(-4)=36-12

\\ \rm\longmapsto h(-4)=24

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