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3 years ago

13

What is the image of (6,-4) after a reflection over the y-axis?

1 answer:

kirill115 [55]3 years ago

3 0

Answer:

(-6,-4)

Step-by-step explanation:

Hope this helps! (:

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Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan

SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola. The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

x = 20

When x = 20, y = 60. So the garden should be 20 ft by 60 ft.

4 0

3 years ago

Whats the lcm for 4 and 36?<br><br>Please show work using Stack it method and Cake method!<br>

Darina [25.2K]

36. U get 36 because 36 divided by 4 equals 9 and 36 and 4 can’t go any further than that.

6 0

3 years ago

Simplify the expression where possible.<br><br> (-5 x 2 ) 3 help please!

MAXImum [283]

The answer to (-5 × 2) 3 = -30.

8 0

3 years ago

Write the equation for a parabola with a focus at (6,-4) and a directrix at y= -7

shtirl [24]

Given:

The focus of the parabola is at (6,-4).

Directrix at y=-7.

To find:

The equation of the parabola.

Solution:

The general equation of a parabola is:

$y=\dfrac{1}{4p}(x-h)^2+k$ ...(i)

Where, (h,k) is vertex, (h,k+p) is the focus and y=k-p is the directrix.

The focus of the parabola is at (6,-4).

$(h,k+p)=(6,-4)$

On comparing both sides, we get

$h=6$

$k+p=-4$ ...(ii)

Directrix at y=-7. So,

$k-p=-7$ ...(iii)

Adding (ii) and (iii), we get

$2k=-11$

$k=\dfrac{-11}{2}$

$k=-5.5$

Putting $k=-5.5$ in (ii), we get

$-5.5+p=-4$

$p=-4+5.5$

$p=1.5$

Putting $h=6, k=-5.5,p=1.5$ in (i), we get

$y=\dfrac{1}{4(1.5)}(x-6)^2+(-5.5)$

$y=\dfrac{1}{6}(x-6)^2-5.5$

Therefore, the equation of the parabola is $y=\dfrac{1}{6}(x-6)^2-5.5$ .

4 0

2 years ago

Please helpp i need this doneee :((

egoroff_w [7]

Answer:

$w = \frac{5}{8}, v = \frac{21}{2}$

Step-by-step explanation:

With given information, we have $\frac{TR}{TQ} = \frac{TS}{TP}$ , so $\frac{5}{13} = \frac{3w}{3w+3}$ , which gives us $w=\frac{5}{8}$ . Meanwhile, we have $\frac{TR}{TQ}=\frac{RS}{QP}$ , so $\frac{5}{13}=\frac{10}{2v+5}$ , which gives us $v = \frac{21}{2}$ .

6 0

2 years ago