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puteri [66]
4 years ago
13

A used car dealer sold two cars for $1980 each. On the first car he made a 10 percent profit. On the second car he took a loss o

f 10 percent. Taken together, did he profit or lose on the deals?
Mathematics
2 answers:
Lelu [443]4 years ago
8 0

Answer:

Step-by-step explanation:

Neither.  He came out even.  The profit made on the first sale was exactly wiped out by the loss on the second sale.

Alex73 [517]4 years ago
5 0

Answer: he neither made profit nor loss on both deals

Step-by-step explanation:

The cost of the first car sold by the car dealer is $1980. On the first car he made a 10 percent profit. This means that the profit made on the first car would be

10/100 × 1980 = 0.1 × 1980 = $198

Amount for which he sold the first car would be

1980 + 198 = $2178

The cost of the second car sold by the car dealer is $1980. On the second car he made a 10 percent loss. This means that the loss made on the second car would be

10/100 × 1980 = 0.1 × 1980 = $198

Amount for which he sold the second car would be

1980 - 198 = $1782

Total cost of both cars = 1980 + 1980 = $3960

Total selling price = 2178 + 1782 = $3960

Profit or loss = selling price - cost price. Therefore

Profit or loss = 3960 - 3960 = $0

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Origin is the corner of square whose one side is 3 X + 4 Y + 5 = 0 find its area.
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The correct option is;

a. 1

Step-by-step explanation:

Given that the origin (0, 0) is the corner of the square

The equation of one of the sides = 3·X + 4·Y + 5 = 0

Therefore, we have;

Y = -3/4·X - 5/4

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The sloe of the perpendicular side from the origin to the given line is therefore = -(1/(3/4)) = 4/3

The y-intercept of the current particular perpendicular side = 0

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The coordinate of the point of intersection of the two sides of the square above is found by equating the two lines to each other as follows;

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The length of a side = √((-3, 5) - 0)² + ((-4, 5) - 0)² = √1 = 1

The area of a square = (Length of side) × (Length of side)

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