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VLD [36.1K]
3 years ago
7

How do i phrase five more than a number to an algebraic expression:

Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

x+5

Step-by-step explanation:

X= the number

x+5= 5 more than the number (represented by x)

Citrus2011 [14]3 years ago
3 0

Answer:

x+5 (you may use any letter instead of x)

Step-by-step explanation:

x (the number)

x + 5 (add 5)

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Number 1 wants you to set up proportions so four numbers equal to 2/1 would be: 6/3 8/4 10/5 12/6, and so on. I'm not sure what they're asking when they say the sum of the first two numbers is equal to 4.8
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2 years ago
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Annette [7]

Answer:

c

Step-by-step explanation: If you do the math you can clearly see and I got the answer correct.

7 0
2 years ago
14 POINTS 14 Points 14 points
viva [34]

Answer:

r = 10 cm

Step-by-step explanation:

r² = 8² + 6²

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3 years ago
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The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe
WARRIOR [948]

Answer:

7536 km^3/sec

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

Volume = \pi r^2h

Where r is the radius and

h is the height of cylinder.

As per question statement:

r = 40 km (variable)

h = 2.5 (constant)

\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h

As \pi, h are constant:

\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec

4 0
2 years ago
Given the volume is 105 inches³ for an 8 pound bowling ball, find the radius of the bowling ball,
mariarad [96]

Answer:

2.92

Step-by-step explanation:

V=\frac{4}{3}\pi r^3 \\ \\ 105=\frac{4}{3}\pi r^3 \\ \\ r^3=\frac{105}{\frac{4}{3}\pi} \\ \\ r=\sqrt[3]{\frac{105}{\frac{4}{3}\pi}}  \\ \\ r \approx 2.92

7 0
1 year ago
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