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Julli [10]
3 years ago
12

The coordinates of the verticies of a rectangle are (-2,3), (4,3), (4,-4) and (-2, -4) what are the demensions of the rectangle?

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0
Jdushuszvusshsushduys sudbrhr did for fun dbd d d did. B. B u igfuf.
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Find the solution set.<br><br> |x| = -16<br><br> { }<br> {-4, 4}<br> {-16, 16}<br> {-32, 32}
Otrada [13]
This an { } solution  because the absolute value is always a positive number unless there is a negative sign in front of the brackets.  

hope this helps :)

7 0
3 years ago
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I still cant figure it out . ughh −2∣5w−7∣+9=−7
Fofino [41]
W=3,-1/5 is the answer
3 0
3 years ago
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What shape would you get if you cut off one of the corners of a rectangular prism
Svetlanka [38]

Answer:

A Pyramid

Step-by-step explanation:

3 0
2 years ago
The output is four times the input
juin [17]
O=4i (is that was you were asking about) 

edit: sorry that wasn't very detailed say if the input is 4 the output will be 16 or if the input is 100 the output will be 400. So mainly what ever the input is multiply it by 4.

I hope this helps :)
5 0
2 years ago
Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3
xxMikexx [17]

Answer:

The answer is 4 + √15 .

Step-by-step explanation:

You have to get rid of surds in the denorminator by multiplying it with the opposite sign :

\frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  -  \sqrt{3} }

=  \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5}  -  \sqrt{3} }  \times  \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}  +  \sqrt{3} }

=  \frac{ {( \sqrt{5} +  \sqrt{3} ) }^{2} }{( \sqrt{5} -  \sqrt{3} )( \sqrt{5}  +  \sqrt{3})  }

=   \frac{ {( \sqrt{5} )}^{2}  + 2( \sqrt{5} )( \sqrt{3}) +  {( \sqrt{3}) }^{2}  }{ {( \sqrt{5}) }^{2} -  { (\sqrt{3} )}^{2}  }

=  \frac{5 + 2 \sqrt{15} + 3 }{5 - 3}

=  \frac{8 + 2 \sqrt{15} }{2}

= 4 +  \sqrt{15}

3 0
2 years ago
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