Hello!
The graph y < -2/3x + 2 has a dotted line. That means that any points on the dotted line or not shaded, is not a solution to this inequality. Since we are given 4 choices, we can substitute those values into the given inequality to see if it is true.
A) (0, 2)
2 < -2/3(0) + 2
2 < 2, this is false.
B) (3, 0)
0 < -2/3(3) + 2
0 < -2 + 2
0 < 0, this is false.
C) (0, 0)
0 < -2/3(0) + 2
0 < 2, this is true.
D). (0, 3)
3 < -2/3(0) + 2
3 < 2, this is false.
To check if choice C) (0, 0) is true, we should look at the given graph.
Since (0, 0) is in the shaded area, and is not graphed on the dotted line, therefore, a solution to this linear inequality is C, (0, 0).
Since we need to find the number of ways they could enter first, second and third place, (I can't demonstrate, but you should get the idea) take 8, 7 and 6 and multiply them, 5-1 we don't need, we just need 8, 7, and 6, multiply those three numbers and you get 336, there you go, 336 ways to organize all 8 girls in first, second and third place, hope this helps
Answer:
12
Step-by-step explanation:
First subtract 7 from 43, 55 and 67
43 - 7 = 36 ; 55 - 7 = 48 ; 67 - 7 = 60
Now find the GCF of 36 , 48 , 60
36 = 2 * 2 * 3 * 3
48 = 2 * 2 * *2*2 * 3
60 = 2 * 2 * 3 * 5
GCF = 2 * 2 * 3 = 12
The required number is 12
When you divide 43 by 12, the remainder is 7.
When you divide 55 by 12, the remainder is 7
When you divide 67 by 12, the remainder is 7
Write down
15-80
Solve it by adding 15 to -80
The final answer is -65
Answer:
d
Step-by-step explanation:
