Show work please!!! Solve the equation by completing the square. If necessary, round to the nearest hundredth.

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

1. B 2. C

Step-by-step explanation:

1. x^2-18x+(18/2)^2=19+(18/2)^2

(x-18/2)^2=100

(x-9)^2=100

x1= -1 x2= 19

2. x^2=81

x=+-9

x1=-9 x2=9

You might be interested in

Candle food is on sale for 20% of the original price what is the discount of the key if the original price is $1.35

Evgesh-ka [11]

Hi there!

To calculate a discount or a mark-up in the price of a retail item, you need to multiply the given price of the item by the percentage, like so:

1.35 × 0.2 = 0.27

Then you add or subtract as necessary. In your case you would subtract since you are trying to find a discount price.

1.35 - 0.27 = 1.08

So the final price of the product after the discount is $1.08

Your friend, ASIAX

5 0

3 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$