Graph the linear equation y=×/3-4

Write the phrase as an expression. Then simplify the expression. The product of 8 and a number y multiplied by 9

Neporo4naja [7]

Answer:

8y x 9 ⇒ 72y

Step-by-step explanation:

5 0

3 years ago

How can I work out 30% of (blank) is 60?

geniusboy [140]

60/ (30/100)
= 60* (100/30)
= 200

The final answer is 200~

3 0

3 years ago

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Anna learns in her science class that the human eye blinks an average of 4,200,000 times a year. What is this number expressed i

Alla [95]

I think 4.2 x 10^6 is the answer you're looking for.

5 0

3 years ago

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The probability that an American company will open a location in Shanghai, China is 0.7. The probability that it will open a loc

kodGreya [7K]

Answer:

Step-by-step explanation:

Given that the probability that an American company will open a location in Shanghai, China is 0.7.

The probability that it will open a location in Beijing, China is 0.4.

The probability that it will open a location in either Shanghai or Beijing or both is 0.8.

the probability that the company will open a location in:

(a) both Shanghai and Beijing :

$0.7+0.4-P(both)=0.8$

P(both) = 0.3

(using addition theory of probability for union of sets)

(b) neither Shanghai nor Beijing

= 1- P(AUB)

$=1-0.8 = 0.2$

(c) Beijing but not in Shanghai?

P(Beiging)_P(both) = $0.4-0.3=0.1$

(d) Shanghai given that it opens a location in Beijing

=P(Both)/P(Beijing) = $\frac{0.3}{0.4} =0.75$

4 0

3 years ago

There is a 70 percent chance that an airline passenger will check bags. In the next 16 passengers that check in for their flight

GenaCL600 [577]

Answer:

a) $P(X=16)=(16C16)(0.7)^{16} (1-0.7)^{16-16}=0.00332$

b) $P(X$

And we can find the individual probabilities like this:

$P(X=10)=(16C10)(0.7)^{10} (1-0.7)^{16-10}=0.1649$

$P(X=11)=(16C11)(0.7)^{11} (1-0.7)^{16-11}=0.2099$

$P(X=12)=(16C12)(0.7)^{12} (1-0.7)^{16-12}=0.2040$

$P(X=13)=(16C13)(0.7)^{13} (1-0.7)^{16-13}=0.1465$

$P(X=14)=(16C14)(0.7)^{14} (1-0.7)^{16-14}=0.0732$

$P(X=15)=(16C15)(0.7)^{15} (1-0.7)^{16-15}=0.0228$

$P(X=16)=(16C16)(0.7)^{16} (1-0.7)^{16-16}=0.0033$

And replacing we got:

$P(X$

c) $P(x \geq 10) = P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)+P(X=16)$

And replacing we got 0.825

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=17, p=0.7)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

And we want to find this probability:

$P(X=16)=(16C16)(0.7)^{16} (1-0.7)^{16-16}=0.00332$

Part b fewer than 10 will check bags

We want this probability:

$P(X$

We can use the complement rule and we have:

$P(X$

And we can find the individual probabilities like this:

$P(X=10)=(16C10)(0.7)^{10} (1-0.7)^{16-10}=0.1649$

$P(X=11)=(16C11)(0.7)^{11} (1-0.7)^{16-11}=0.2099$

$P(X=12)=(16C12)(0.7)^{12} (1-0.7)^{16-12}=0.2040$

$P(X=13)=(16C13)(0.7)^{13} (1-0.7)^{16-13}=0.1465$

$P(X=14)=(16C14)(0.7)^{14} (1-0.7)^{16-14}=0.0732$

$P(X=15)=(16C15)(0.7)^{15} (1-0.7)^{16-15}=0.0228$

$P(X=16)=(16C16)(0.7)^{16} (1-0.7)^{16-16}=0.0033$

And replacing we got:

$P(X$

Part c at least 10 bags

We can find this probability like this:

$P(x \geq 10) = P(X=10)+P(X=11)+P(X=12)+P(X=13)+P(X=14)+P(X=15)+P(X=16)$

And replacing we got 0.825

4 0

3 years ago