Answer:
4^1/3 is greatest among the given
Step-by-step explanation:
√2 , 4^1/3 , 3^1/4
Find the LCM of 2, 3 , 4= 12
i ) √2 =2^1/2 = 2^6/12=(2^6)^1/12
= (64)^1/12
ii ) 4^1/3 = 4^4/12 = (4^4)^1/12
= (256)1/12
iii )3^1/4 = 3^3/12 = ( 3³ )^1/12
= (27)^1/12
Therefore ,
(256)^1/12 > (64)^1/12 > (27)^1/12
4^1/3 > 2^1/2 > 3^1/4
4^1/3 is greatest among the given
number
V = 130 mL
m = 0.250 lb = 113.398 g
Density: d = m/V
d = 113.398 g / 130 mL
d = 0.8722923 g / mL
Answer:5. 291503
Step-by-step explanation:
√28
2√7
5. 291503
