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Ede4ka [16]
3 years ago
8

Use the function rule z = 2x + 3.

Mathematics
1 answer:
musickatia [10]3 years ago
3 0

Step-by-step explanation:

Z = 2x + 3

Putting value of x

Z = 2( - 16.7) + 3

Z = - 33.4 + 3

Z= - 30.4

Option B is the correct answer

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i have been struggling for this work that has been assigned to me at the first day of school after a long time.
maria [59]

Answer:

Fill the gaps in this sequence:

25 36 <u>49</u> 64 81 <u>100</u>

This sequence is the numbers 5, 6, 7, 8, 9, and 10 squared.

Work out the cube root of 343, then square it.

<u>49</u>

Since 7 cubed equals 343, then 7 squared is 49.

When you subtract one square number from another the answer is 7.

What are the two square numbers?

<u>16</u> and <u>9</u>

These are the only squares that fit the criteria.

Write down a number you can square to give an answer bigger than 200 but smaller than 300.

<u>15, 16, 17</u>

All of those answers work. 15² is 225, 16² is 256, and 17² is 289. You can choose any of them to enter in and it should work.

7 0
3 years ago
Based on the table, what is Nick's rate?
Murrr4er [49]
21 /3 = 7
35 / 5 = 7
63 / 9 = 7

 his rate is B. 7 yds/sec

5 0
3 years ago
Read 2 more answers
Which set is finite?
Tanzania [10]
Hello,

Answer A is the only finite set.
8 0
3 years ago
You might need:
aleksley [76]

Answer: ummm

Step-by-step explanation:

5 0
2 years ago
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In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
3 years ago
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