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3 years ago

Why dont the nuclei have permanent electric dipole

Physics

1 answer:

romanna [79]3 years ago

4 0

Answer and explanation:

The nuclei don't have a permanent electric dipole because they have a positive homogeneous distributed net charge. The requirement for the existence of a permanent electric dipole is that the body has positive and negative charges distributed in an inhomogeneous way, where positive and negative charges are well-differentiated and incapable of mooving its relative position. This is exactly what happens with molecules.

Magnetic dipole moments are related to sub particle movement inside atomic particles. That's why nuclei and molecules have it.

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Item 19 A student with arms outstretched stands on a platform that is rotating with a constant angular speed. The student then p

nadezda [96]

Answer:

An increase in angular speed due to conservation of energy priciple.

Explanation:

This leads to a decrease in your moment of inertia. This means that your angular velocity must increase as a result of conservation of energy principle and therefore you will spin faster.

It's also the same way this conservation of energy principle applies to ice skaters that makes them spin faster when they suddenly draw their arms inwards.

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3 years ago

Which of these BEST describes the concept of the rock cycle?

choli [55]

D rocks are continually changing and type of rock mat be transformed into another type of appropriate process.

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3 years ago

Which of the following is NOT a characteristic of a planet?

stepladder [879]

Answer:

1: body of significant size

Explanation:

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5 0

3 years ago

If the boy and his bike actually had a mass of 40 kg instead of 50 kg how much force would it take for him to accelerate at 0.8

klio [65]

Answer:

F = 32 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N] (units of Newtons)

m = mass = 40 [kg]

a = acceleration = 0.8 [m/s²]

Now replacing:

$F=m*a\\F = 40*0.8\\F = 32 [N]$

8 0

3 years ago

A 2.0-mm-diameter copper ball is charged to 40 nC . What fraction of its electrons have been removed? The density of copper is 8

murzikaleks [220]

Answer:

0.02442 × 10⁻⁹

Explanation:

Given:

Diameter of copper ball = 2.00 mm = 0.002 m

Charge on ball = 40 nC = 40 × 10⁻⁹ C

Density of copper = 8900 Kg/m³

Now,

The number of electrons removed, n = $\frac{\textup{Charge on ball}}{\textup{Charge of an electron}}$

also, charge on electron = 1.6 × 10⁻¹⁹ C

Thus,

n = $\frac{40\times10^{-9}}{1.6\times10^{-19}}$

n = 25 × 10¹⁰ Electrons

Now,

Mass of copper ball = volume × density

Mass of copper ball = $\frac{4}{3}\pi(\frac{d}{2})^3$ × 8900

Mass of copper ball = $\frac{4}{3}\pi(\frac{0.002}{2})^3$ × 8900

Mass of copper ball = 0.03726 grams

Also,

molar mass of copper = 63.546 g/mol

Therefore,

Number of mol of copper in 0.03726 grams = $\frac{ 0.03726}{63.546}$

Number of mol of copper in 0.03726 grams = 5.86 × 10⁻⁴ mol

and,

1 mol of a substance contains = 6.022 × 10²³ atoms

Therefore,

5.86 × 10⁻⁴ mol of copper contains = 5.86 × 10⁻⁴ × 6.022 × 10²³ atoms.

5.86 × 10⁻⁴ mol of copper contains = 35.88 × 10¹⁹ atoms

Now,

A neutral copper atom has 29 electrons.

Therefore,

Number of electrons in ball = 29 × 35.88 × 10¹⁹ = 1023.37 × 10¹⁹ electrons.

Hence,

The fraction of electrons removed = $\frac{25\times10^{10}}{1023.37\times10^{19}}$

The fraction of electrons removed = 0.02442 × 10⁻⁹

3 0

4 years ago