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r-ruslan [8.4K]
3 years ago
9

Which of these BEST describes the concept of the rock cycle?

Physics
1 answer:
choli [55]3 years ago
8 0
D  rocks are continually changing and type of rock mat be transformed into another type of appropriate process.

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Why do black holes have a large gravitational pull that even light cannot escape from
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Answer:

Because matter has been squeezed into a tiny space.

Explanation:

According to NASA, this can happen when a star is dying.

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Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
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Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

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A trooper is moving due south along the freeway at a speed of 23 m/s. at time t = 0, a red car passes the trooper. the red car m
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The answer choice is 23
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You observe a star system for many weeks. The light curve does not show significant changes in brightness, but a series of spect
mariarad [96]

Based on the changes in the light curve and the behavior of the series of spectra, this is a<u> binary system. </u>

<h3>How is this is binary system?</h3>

The characteristics described are those of a binary system with the specific type of system being the spectroscopic binary system.

This is because in a spectroscopic binary system, there won't be significant changes in brightness but as a result of stars orbiting towards and then away from us, spectral features will appear as alternative absorption lines.

In conclusion, this is a binary system.

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Current what can do work in an electric device
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It could help transport important information
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