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stepladder [879]
4 years ago
13

An oscillator vibrating at 1270 Hz produces a sound wave that travels through an ideal gas at 325 m/s when the gas temperature i

s 22.0 ∘C. For a certain experiment, you need to have the same oscillator produce sound of wavelength 28.5 cm in this gas What should the gas temperature be to achieve this wavelength?

Physics
2 answers:
REY [17]4 years ago
8 0

Answer:

     T = 53.44 ° C

Explanation:

For this exercise we will use the relationship between the speed of sound and the wavelength and frequency

          v = λ f

          v = 0.285 1270

          v = 361.95 m / s

The speed of sound is related to temperature in degrees Celsius

          v = 331 √(1 + T / 273)

          v² / 331² = 1 + T / 273

          T / 273 = v² / 331² -1

            T = 273 (v² / 331² -1)

             

Let's calculate

        T = 273 (361.95²/331² -1)

        T = 53.44 ° C

andrew11 [14]4 years ago
5 0

Explanation:

Below is an attachment containing the solution.

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1.) What type of energy is associated with motion? Kinetic energy

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8 0
3 years ago
A small boat is moving at a velocity of 1.93 m/s when it is accelerated by a river current perpendicular to the initial directio
olasank [31]

Answer:

16.405m/s

Explanation:

Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?

Using the first equation of linear motion,

v = u + at

v = 1.93 + 0.750 x 19.3

v = 1.93 + 14.475

v = 16.405m/s

7 0
3 years ago
Read 2 more answers
The graph is tied to the reading
AleksandrR [38]
I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.

ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.

iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.

iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
5 0
3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo
djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

f_s = \mu_s N --- (1)

where;

f_s = static friction force

\mu_s = coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

N = ma_{min}

From equation (1)

f_s = \mu_s ma_{min}

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

F = f_s

mg = \mu_s ma_{min}

a_{min} = \dfrac{mg }{ \mu_s m}

a_{min} = \dfrac{g }{ \mu_s }

where;

\mu_s = 0.383 and g = 9.8 m/s²

a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }

\mathbf{a_{min}= 25.59 \ m/s^2}

3 0
3 years ago
How do you know if an experimental result is acceptable or trustworthy? What gives you confidence that your data are trustworthy
Virty [35]

Explanation:

For an experimental result to be considered acceptable, all relevant variables involved in the experiment must be taken into account, by isolating it, performing it under controlled conditions and modifying the conditions under which it takes place. This, with the objective of excluding alternative explanations in the analisis of the experimental data. Therefore, if these steps are followed appropriately, experimental data are trustworthy. The reliability of the experiment increases when it is replicated by other researchers and the same results are obtained.

6 0
4 years ago
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