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Sphinxa [80]
3 years ago
14

Enter an equation and an answer to the following question:

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0
If you take 10% of $35 yuo get $3.50, and then add that on and 35 + 3.5 = 38.50 so the original price is $38.5
xz_007 [3.2K]3 years ago
6 0
100÷10= 10 ×35= $350 therefore the answer is $350
to try if it is right
10%of 350 =35.so the answer is $350
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The plans for a shed call for a rectangular floor with a perimeter of 204 ft. The length is two times the width. Find the length
Harlamova29_29 [7]
A-length
b-width
perimeter of rectangular floor: 2a+2b=204
<span>The length is two times the width: a=2b
</span>2a + 2b = 204
2*2b + 2b = 204
6b = 204|:6
b = 34
a=2b=2*34=68

a=68->length
b=34->width
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3 years ago
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An ant can crawl 3/4 of a yard in 1/2 minute. How long will it take for the ant to crawl 12 yards?​
Elan Coil [88]

Answer:

6 mins

Step-by-step explanation:

An ant can crawl 3/4 of a yard in 1/2 minute. How long will it take for the ant to crawl 12 yards?​

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3 years ago
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Find the value of x in the isosceles triangle shown below.
miss Akunina [59]

Answer:

D. x=4

Step-by-step explanation:

We can solve this with the Pythagorean Theorem for the right triangle that we can see (which is half of the triangle).

The bottom length is 3 and the hypotenuse is 5.

The Pythagorean Theorem is a²+b²=c².

We can plug this in:

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8 0
2 years ago
10 points please help with calculus HW
Dafna1 [17]

a. The equation of the tangent at (1,3) is y = -x/3 + 10/3

b. The equation of the normal at (1,3) is y = 3x

c. Find the graph in the attachment

<h3>a. How to find the equation of the tangent at (1, 3)?</h3>

Since x² + y² = 10, we differentiate the equation with respect to x to find dy/dx which the the equation of the tangent.

So, x² + y² = 10

d(x² + y²)/dx = d10/dx

dx²/dx + dy²/dx = 0

2x + 2ydy/dx = 0

2ydy/dx = -2x

dy/dx = -2x/2y

dy/dx = -x/y

At (1,3), dy/dx = -1/3

Using the equation of a straight line in slope-point form, we have

m = (y - y₁)/(x - x₁) where

  • m = gradient of the tangent = dy/dx at (1,3) = -1/3 and
  • (x₁, y₁) = (1,3)

So, m = (y - y₁)/(x - x₁)

-1/3 = (y - 3)/(x - 1)

-(x - 1) = 3(y - 3)

-x + 1 = 3y - 9

3y = -x + 1 + 9

3y = -x + 10

3y + x = 10

y = -x/3 + 10/3

So, the equation of the tangent at (1,3) is y = -x/3 + 10/3

<h3>b. The equation of the normal at the point (1, 3)</h3>

Since the tangent and normal line are perpendicular at the point, for two perpendicular line,

mm' = -1 where

  • m = gradient of tangent = -1/3 and
  • m' = gradient of normal

So, m' = -1/m

= -1/(-1/3)

= 3

Using the equation of a straight line in slope-point form, we have

m' = (y - y₁)/(x - x₁) where

  • m' = gradient of normal at (1, 3)  and (
  • x₁, y₁) = (1,3)

So, m = (y - y₁)/(x - x₁)

3 = (y - 3)/(x - 1)

3(x - 1) = (y - 3)

3x - 3 = y - 3

y = 3x - 3 + 3

y = 3x + 0

y = 3x

So, the equation of the normal at (1,3) is y = 3x

c. Find the graph in the attachment

Learn more about equation of tangent and normal here:

brainly.com/question/7252502

#SPJ1

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Is -8 a term<br><br> True or false
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Answer:

I believe it is true.

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