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3 years ago

Which number is a rational number A. 7 B. 7.07.... C. 8.12.... D. 9.94...

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

7 0

Answer:

A

Explanation:

All of the other choices are ongoing decimals which make the irrational numbers

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lianna [129]

Answer:

Step-by-step

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2 years ago

A circle with a radius of 15.4 meters. Which statements are true about the circle shown? Check all that apply. The diameter of t

Dafna1 [17]

Step-by-step explanation:

the diameter of a circle is simply 2×radius.

2×15.4 = 30.8 m

the diameter is 30.8 m is true.

the circumference of a circle is

2×pi×radius

2×pi×15.4 = 30.8×pi m

the circumference is 30.8pi m is true.

therefore, the circumference can be found using

2(pi)(15.4)

is true.

now, doing the pi multiplication :

30.8 × pi = 96.76105373... m

the approximate circumference is 96.7 m is true.

6 diameters would be

30.8×6 = 184.8 m

that is much longer than the circumference.

so, more than 6 diameters could be wrapped around the circle is false, if we understand it that this is supposed to wrap the circle once without any overhanging remainder.

5 0

2 years ago

Let A = {a, b, c}, B = {b, c, d}, and C = {b, c, e}. (a) Find A ∪ (B ∩ C), (A ∪ B) ∩ C, and (A ∪ B) ∩ (A ∪ C). (Enter your answe

wariber [46]

Answer:

(a)

$A\ u\ (B\ n\ C) = \{a,b,c\}$

$(A\ u\ B)\ n\ C = \{b,c\}$

$(A\ u\ B)\ n\ (A\ u\ C) = \{b,c\}$

$(A\ u\ B)\ n\ C = (A\ u\ B)\ n\ (A\ u\ C)$

(b)

$A\ n\ (B\ u\ C) = \{b,c\}$

$(A\ n\ B)\ u\ C = \{b,c,e\}$

$(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}$

$A\ n\ (B\ u\ C) = (A\ n\ B)\ u\ (A\ n\ C)$

(c)

$(A - B) - C = \{a\}$

$A - (B - C) = \{a,b,c\}$

They are not equal

Step-by-step explanation:

Given

$A= \{a,b,c\}$

$B =\{b,c,d\}$

$C = \{b,c,e\}$

Solving (a):

$A\ u\ (B\ n\ C)$

$(A\ u\ B)\ n\ C$

$(A\ u\ B)\ n\ (A\ u\ C)$

$A\ u\ (B\ n\ C)$

B n C means common elements between B and C;

So:

$B\ n\ C = \{b,c,d\}\ n\ \{b,c,e\}$

$B\ n\ C = \{b,c\}$

So:

$A\ u\ (B\ n\ C) = \{a,b,c\}\ u\ \{b,c\}$

u means union (without repetition)

So:

$A\ u\ (B\ n\ C) = \{a,b,c\}$

Using the illustrations of u and n, we have:

$(A\ u\ B)\ n\ C$

$(A\ u\ B)\ n\ C = (\{a,b,c\}\ u\ \{b,c,d\})\ n\ C$

Solve the bracket

$(A\ u\ B)\ n\ C = (\{a,b,c,d\})\ n\ C$

Substitute the value of set C

$(A\ u\ B)\ n\ C = \{a,b,c,d\}\ n\ \{b,c,e\}$

Apply intersection rule

$(A\ u\ B)\ n\ C = \{b,c\}$

$(A\ u\ B)\ n\ (A\ u\ C)$

In above:

$A\ u\ B = \{a,b,c,d\}$

Solving A u C, we have:

$A\ u\ C = \{a,b,c\}\ u\ \{b,c,e\}$

Apply union rule

$A\ u\ C = \{b,c\}$

So:

$(A\ u\ B)\ n\ (A\ u\ C) = \{a,b,c,d\}\ n\ \{b,c\}$

$(A\ u\ B)\ n\ (A\ u\ C) = \{b,c\}$

The equal sets

We have:

$A\ u\ (B\ n\ C) = \{a,b,c\}$

$(A\ u\ B)\ n\ C = \{b,c\}$

$(A\ u\ B)\ n\ (A\ u\ C) = \{b,c\}$

So, the equal sets are:

$(A\ u\ B)\ n\ C$ and $(A\ u\ B)\ n\ (A\ u\ C)$

They both equal to $\{b,c\}$

So:

$(A\ u\ B)\ n\ C = (A\ u\ B)\ n\ (A\ u\ C)$

Solving (b):

$A\ n\ (B\ u\ C)$

$(A\ n\ B)\ u\ C$

$(A\ n\ B)\ u\ (A\ n\ C)$

So, we have:

$A\ n\ (B\ u\ C) = \{a,b,c\}\ n\ (\{b,c,d\}\ u\ \{b,c,e\})$

Solve the bracket

$A\ n\ (B\ u\ C) = \{a,b,c\}\ n\ (\{b,c,d,e\})$

Apply intersection rule

$A\ n\ (B\ u\ C) = \{b,c\}$

$(A\ n\ B)\ u\ C = (\{a,b,c\}\ n\ \{b,c,d\})\ u\ \{b,c,e\}$

Solve the bracket

$(A\ n\ B)\ u\ C = \{b,c\}\ u\ \{b,c,e\}$

Apply union rule

$(A\ n\ B)\ u\ C = \{b,c,e\}$

$(A\ n\ B)\ u\ (A\ n\ C) = (\{a,b,c\}\ n\ \{b,c,d\})\ u\ (\{a,b,c\}\ n\ \{b,c,e\})$

Solve each bracket

$(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}\ u\ \{b,c\}$

Apply union rule

$(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}$

The equal set

We have:

$A\ n\ (B\ u\ C) = \{b,c\}$

$(A\ n\ B)\ u\ C = \{b,c,e\}$

$(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}$

So, the equal sets are:

$A\ n\ (B\ u\ C)$ and $(A\ n\ B)\ u\ (A\ n\ C)$

They both equal to $\{b,c\}$

So:

$A\ n\ (B\ u\ C) = (A\ n\ B)\ u\ (A\ n\ C)$

Solving (c):

$(A - B) - C$

$A - (B - C)$

This illustrates difference.

$A - B$ returns the elements in A and not B

Using that illustration, we have:

$(A - B) - C = (\{a,b,c\} - \{b,c,d\}) - \{b,c,e\}$

Solve the bracket

$(A - B) - C = \{a\} - \{b,c,e\}$

$(A - B) - C = \{a\}$

Similarly:

$A - (B - C) = \{a,b,c\} - (\{b,c,d\} - \{b,c,e\})$

$A - (B - C) = \{a,b,c\} - \{d\}$

$A - (B - C) = \{a,b,c\}$

They are not equal

4 0

3 years ago

Which of the following possibilities will form a triangle? (5 points)

nevsk [136]

Answer:

Side = 16 cm, side = 9 cm, side = 8 cm

Step-by-step explanation:

Side = 16 cm, side = 9 cm, side = 8 cm

6 0

2 years ago

Plz explain and prove the triangles congruence.

ziro4ka [17]

Answer:

The explanation is given below with the diagram.

Step-by-step explanation:

Given:

Δ ABC is an Isosceles triangle with base AB.

D is the midpoint of AB

∴ AD = BD

To Prove:

$\angle ACD \cong \angle BCD$

Proof:

Isosceles triangle property:

If Δ ABC is an Isosceles triangle with base AB, then the two sides are congruent and the base angles are congruent.

$\therefore \overline{AC} \cong \overline {BC}\ and\\\therefore \angle CAD} \cong \angle CBD$

$In\ \triangle ACD\ and\ \triangle BCD\\\overline{AC} \cong \overline{BC}\ \textrm{ Two sides of Isosceles Triangle are congruent}\\\angle CAD \cong \angle CBD\ \textrm{Base angles of Isosceles Triangle are congruent }\\\overline{AD} \cong \overline{BD}\ \textrm{ D is the midpoint of AB given}\\\therefore \triangle ACD \cong \triangle BCD\ \textrm{ By Side-Angle-Side test}\\\therefore \angle ACD \cong \angle BCD\ \textrm{corresponding parts(angles) of congruent triangles}\\$

$\therefore \angle ACD \cong \angle BCD\ \textrm{ Proved}$

7 0

3 years ago