Question

A) What is the derivative of x^2 - 6x +36.

Answer 1

Answer:

2x-6

Step-by-step explanation:

Answer 2

Answer:

$2x - 6$

$x=3 \rightarrow \ minimum \ point$

Step-by-step explanation:

$f(x) = x^2 - 6x +36$

The derivative is: $f'(x)= 2x - 6$

To calculate the max/min point of the function, we use the first derivative and put it equal to zero (if needed)

$f'(x) = 2x - 6 = 0\\2x - 6 = 0\\2x = 6\\x = 3$

To check whether this point is max or min, we substitute the value of x in the second derivative of the function. If the answer is positive, the value is minimum. If the answer is negative, the value is minimum.

$f''(x) = 2$

The second derivative is positive, hence $x = 3$ is minimum.