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Igoryamba
2 years ago
15

The population of the African country of Madagascar in 2018 is about 26 million. The estimated population of Madagascar is given

by the function P(t)=26(1.03)t , where t represents the time in years since 2018 and P(t) represents the population in millions.
part a. In 2020 , the population will be blank million
part b. What is the meaning of P(t)=50 ?


The population 50 years after 2018 is P(t) ,
The population 50 years after 2018 is cap p times t, ,

The population t years after 2018 is 50 million.
The population t years after 2018 is 50 million.

The population 50 years after 2018 is 50 million.
The population 50 years after 2018 is 50, million.

The population t years after 2018 is about 114 million.
Mathematics
1 answer:
MrRissso [65]2 years ago
6 0

Answer:

The current population of Madagascar is 28,354,778 as of Thursday, June 10, 2021, based on Worldometer elaboration of the latest United Nations data.

Madagascar 2020 population is estimated at 27,691,018 people at mid year according to UN data.

Madagascar population is equivalent to 0.36% of the total world population.

Madagascar ranks number 51 in the list of countries (and dependencies) by population.

The population density in Madagascar is 48 per Km2 (123 people per mi2).

The total land area is 581,795 Km2 (224,632 sq. miles)

38.5 % of the population is urban (10,670,252 people in 2020)

The median age in Madagascar is 19.6 years.

Step-by-step explanation: i dont know man

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Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.
skad [1K]

Answer:

The absolute maximum and minimum is 20\; \text{and} -20.

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

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f_x=y-4=0

f_y=x=0

The only solution to this system of equations is the point (0, 4), which lies in the domain.

f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1

\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1

\therefore (0,4) is a saddle point.

Boundary points -  (4,0),  (-4,0), (0,16)

Along boundary  y=16-x^2

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=16x-x^3-4x

\Rightarrow f^'=16-3x^2-4=0

\Rightarrow 3x^2=12

\Rightarrow x=\pm2,\;\;y=14

Values of f(x) at these points.

\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}

Therefore, the absolute maximum and minimum is 20\; \text{and} -20.

6 0
3 years ago
If <img src="https://tex.z-dn.net/?f=x-12%5Csqrt%7Bx%7D%20%2B36%3D0" id="TexFormula1" title="x-12\sqrt{x} +36=0" alt="x-12\sqrt{
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Answer:

x = 36

Step-by-step explanation:

x - 12\sqrt{x} + 36 = 0

Subtract x and 36 from both sides.

-12\sqrt{x} = -x - 36

Divide both sides by -1.

12\sqrt{x} = x + 36

Square both sides.

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Subtract 144x from both sides.

0 = x^2 - 72x + 1296

Factor the right side.

0 = (x - 36)^2

x - 36 = 0

x = 36

Since the solution of the equation involved squaring both sides, we musty check the answer for possible extraneous solutions.

Check x = 36:

x - 12\sqrt{x} + 36 = 0

36 - 12\sqrt{36} + 36 = 0

36 - 12\times 6 + 36 = 0

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0 = 0

Since 0 = 0 is a true statement, the solution x = 36 is a valid solution.

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