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DIA [1.3K]
3 years ago
7

Chain of hemoglobin is 1 m.u. from the albino locus. assume for the moment that the same is true in humans. the disease sickle-c

ell anemia is the result of homozygosity for a particular mutation in the β-globin gene.
Biology
1 answer:
sergeinik [125]3 years ago
3 0
*Sickle cell disease is a constitutional corpuscular hemolytic anemia related to an abnormal structure of the globin chain. It is an autosomal recessive disease, which means homozygosity is necessary to fully express the illness.
*It corresponds to the synthesis of an abnormal hemoglobin, HbS, which is different from normal Hb (HbA).

*The S allele (located in the chromosome 11), responsible for the anomaly, is especially widespread in the African continent, it is also found in other regions of the Mediterranean.
<span>
*Mutation GAG to GTG
leading to the substitution Glutamine by a valine in position 6 of the chain of the globine.</span>
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<h3>How to calculate genotype of a cross?</h3>

According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.

If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:

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Learn more about genotype at: brainly.com/question/12116830

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