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3 years ago

Please can someone help me find X using sin cos and tan

Mathematics

2 answers:

olga_2 [115]3 years ago

3 0

$\sin30^\circ=\dfrac x{25}$

$\implies x=25\sin30^\circ=\dfrac{25}2$

RSB [31]3 years ago

3 0

Answer:

12.5.

Step-by-step explanation:

sin 30 = opposite / hypotenuse:

sin 30 = x / 25

x = 25 sin 30

= 1/2 * 25

= 12.5.

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what does it mean when the will says tomorrow it's ashes will be scattered to the four winds in the westing game

katovenus [111]

Answer:

In the document, Westing names the sixteen heirs present as his “nieces and nephews” and says that tomorrow his ashes “will be scattered to the four winds.” He then asserts that his life has been taken by one of his heirs, and he promises that the heir who finds something will receive the inheritance

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.

Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = $30C5 = \frac{30 !}{(30-5)!5!} \\$

$30C5 = 142506$ ways

Number of ways of selecting 5 good bulbs from 26 bulbs = $26C5 = \frac{26 !}{(26-5)!5!} \\$

$26C5 = 65780$ ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = $\frac{26C4 * 4C1}{30C5}$

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) = $\frac{26C3 * 4C2}{30C5}$

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) + Pr(2 defective) + Pr(3 defective) + Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) = $\frac{26C2 * 4C3}{30C5}$

Pr(3 defective) = 0.009

Pr(4 defective) = $\frac{26C1 * 4C4}{30C5}$

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0

3 years ago

I am trying to graduate HS please help me out!!!

vichka [17]

1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:

A=(b1+b2/2)h

A is the area of the trapezoid.
 b1 is the larger base of the trapezoid (b1=16-4=12 ft).
 b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
 h is the height of the trapezoid (h=12-4=8 ft)

2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:

A=(b1+b2/2)h
 A=(12 ft+6 ft/2)(8 ft)
 A=9 ftx8ft
 A=72 ft²

3. The length of fencing is: a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft

6 0

3 years ago

An angle measures 61º. What is the measure of its supplement? HELP ME PLEASE

Irina-Kira [14]

The supplement of 61 degree is 119 degrees
180-61=119

3 0

3 years ago

A recipe calls for 3/4 cup of sugar.

zubka84 [21]

6
I multiplied both the numbers and got that, hope this helped

3 0

3 years ago

Please can someone help me find X using sin cos and tan​

Please can someone help me find X using sin cos and tan