<span>I can solve for x and y
A) 2x - 4y = 12
A) 2x = 4y + 12
A) x = 2y + 6
Substituting into B
B) 3* (2y +6) - 5y = 20
B) 6y + 18 -5y = 20
B) y = 2
B) x = 10
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Answer:
see explanation
Step-by-step explanation:
Inequalities of the type | x | > a, always have solutions of the form
x < - a or x > a
This can be extended to expressions, that is
14 - 5x < - 8 OR 14 - 5x > 8 ( subtract 14 from both sides of both inequalities )
- 5x < - 22 OR - 5x > - 6
Divide both sides by - 5 , reversing the inequality sign as a consequence
x >
OR x < 
That is the solution is
x <
OR x > 
I will show you the steps on how you get that answer and if you have any questions after that let me know and I'd be more than happy to help answer them for you.
The first step for solving (1 + y)² is to use the equation (a + b)² = a² + 2ab + b² to expand the expression.
1² + 2 × 1y + y²
1 raised to any power equals 1,, so remove the power.
1 + 2 × 1y + y²
Calculate the product of 2 × 1y.
1 + 2y + y²
Finally,, use the commutative property to reorder the terms.
y² + 2y + 1
Let me know if you have any further questions.
:)