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dybincka [34]
3 years ago
7

The perimeters of the square and the regular pentagon are equal. A square with side lengths of 3x + 3. A pentagon with side leng

ths of x + 8. What is the perimeter of each polygon?
Mathematics
3 answers:
Firlakuza [10]3 years ago
6 0

Answer:

40 hope this helps have a great day

elena55 [62]3 years ago
5 0

Answer:

The answer is Not 40 idk what it is

Step-by-step explanation:

Bapi2 years ago
0 0

guys its 42

Bapi
2 years ago
not 40
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Find each product mentally. show the steps you used.7 × 2.9
JulijaS [17]
Answer is 20.3 and the steps are:
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6 0
3 years ago
In circle o, the length of radius OL is 6 cm and the length
AlekseyPX

Answer:

14.2cm

Step-by-step explanation:

The diagram representing the circle and its attributes has been attached to this response.

<em>As shown in the diagram;</em>

The circle is centered at o,

The length of radius OL = 6cm

The length of the arc LM = 6.3cm

The angle MON = 75°

The angle LOM = θ

<em>Remember that;</em>

The length, L, of an arc is given by;

L = (θ / 360) x (2πr)         -------------(i)

Where;

θ is the angle subtended by the arc

r = radius of the circle.

Using the formula in equation (i), let's calculate the angle θ subtended by arc LM as follows;

L = (θ / 360) x (2πr)  

Where;

L = length of arc LM = 6.3cm

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation to get;</em>

6.3 = (θ / 360) x (2 x π x 6)

6.3 = (θ / 360) x (12 x π)

6.3 = (θ / 30) x (π)              [Take π = 22/7]

6.3 = (θ / 30) x (22 / 7)

θ = \frac{6.3*30*7}{22}

θ = 60.14°

Therefore, the angle subtended by arc LM is 60.14°

Now, from the diagram,

The angle subtended by arc LMN is;

θ + 75° = 60.14° + 75° =  135.14°

Let's now calculate the length of arc LMN using the same equation (i)

L = (θ / 360) x (2πr)  

Where;

L = length of arc LMN

θ = angle subtended by LMN = 135.14°

r = radius of the circle = length of radius OL = 6cm

<em>Substitute these values into the equation;</em>

L = (135.14° / 360°) x (2 x π x 6)             [Take π = 22/7]

L = 14.15cm

Therefore, the length of arc LMN is 14.2cm to the nearest tenth.

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