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Ilya [14]
3 years ago
7

Suppose a three-seat city council election. For each seat, one progressive and one conservative is running, and voters must choo

se between one of the two candidates. Further suppose there are more conservative than progressive voters, such that the probability of a conservative candidate winning is 0.6. (a) What is the probability that the conservative party wins all three seats? (b) What is the probability that the conservative party wins exactly two seats?
Mathematics
1 answer:
Kitty [74]3 years ago
5 0

Answer:

The probability that conservative party wins all 3 seats is 0.216

The probability that conservative party wins exactly two seats is 0.432

Step-by-step explanation:

Consider the provided information.

The probability of a conservative candidate winning is p=0.6.

The probability of one progressive candidate will win is: 1-0.6=0.4

Part (a) What is the probability that the conservative party wins all three seats?

According to binomial distribution: b(x; n, p) =^nC_xp^x(1- p)^{n-x}

P(x=3) =^3C_3(0.6)^3 (0.4)^{3-3}

P(x=3) =(0.6)^3

P(x=3)=0.216

P(conservative party wins all 3 seats) = 0.216

Hence, the probability that conservative party wins all 3 seats is 0.216

Part (a) What is the probability that the conservative party wins exactly two seats?

P(x=2) =^3C_2(0.6)^2 (0.4)^{3-2}

P(x=2) =3(0.36)(0.4)

P(x=2) =0.432

Hence, the probability that conservative party wins exactly two seats is 0.432

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Answer:

9x^2(5y^2 + 2x).

Step-by-step explanation:

First find the Greatest Common Factor of the 2 terms.

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The complete GCF is therefore 9x^2.

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The three positions are not on the same line.

Step-by-step explanation:

We have three points: A:(3,2,0),  B:(1,-1,2) and C:(5,5,2).

Let's build a vector that goes from one point to another; that vector will be the director of a line (if we draw a vector that goes from A to B, that vector will be the direction of the line that pass by A and B because it does not change). In order to build that vector, let's subtract B from A:

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The equation of a line is:

p=p_0+rt

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Now we have the director vector: (2,3,-2), and we can verify that A and B are on the line:

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Because there is a value for t that satisfies both A and B: If we do p_0=(3,2,0) and t=0, we are going to obtain the point p=A; and if we do t=-1, we are going to obtain p=B. Let's see that:

p=(3,2,0)+(2,3,-2)*0=(3,2,0)\\p=A\\p=(3,2,0)+(2,3,-2)*-1=(1,-1,2)\\p=B\\

If C is also in the same line, C must accomplish the equation: p=(3,2,0)+(2,3,-2)t, so:

C=(5,5,2)=(3,2,0)+(2,3,-2)t

Let's simplify the equation writing the parametric equation, which is just to write the equation for each dimension:

5=3+2t\\5=2-3t\\2=-2t\\

You can verify that there is not a value of t that satisfies all three equations, so, the point C is not on the same line as A and B; which means that A, B and C are not on the same line.

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Step-by-step explanation:

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